Physics, asked by hasti3058, 10 months ago

calculation the molarity of HNO3 Solution prepared by dissolving 6.022×10^molecules in 10L solution.(ME HNO3=63g/mol)

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Answered by Anonymous

molecule of HNO3=6.022×10^23

moles

= mass/ molar mass= molecule of HNO3/ Na

mass=6.022×10^23×63/6.022×10^23

mass=63g

moles= 1

Molarity

= moles HNO3/ vol soln

=1/10

=0.1M

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Answered by abctjryjyjbfs4675

here is your answer mate !!

Hope, it helps you !!

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