Question

calculations of factor
1 mole of sodium nitrate =one mole of sulphanilamide
1000 ml of 1 M NaNO2= molecular weight of sulphanilamide
1000 ml of 1 M of NaNO2=172.2g of sulphanilamide
1 ml of 0.1 M NaNo2=________g of sulphalinamide
​

Answer 1

Answer:

1 mole of sodium nitrate = one mole of sulphatanilamide1000ml of 1 m na no 2............