Question

Calcule los moles de nitrato de cobre ,Cu(NO3), que se producen si se hacen reaccionar 231.5 gramos de ácido nítrico (HNO3 )

8HNO3 + 3·Cu → 3Cu(NO3)2 + 2NO + 4H2O

Answer 1

Answer:

Value added : Firm A= Rs. 500; Firm B= Rs. 500; Firm C= Rs. 800; Firm D= Rs. 800. (ii) Rs. 2600.

Answer 2

Explanation:

3Cu+8HNO

3

→3Cu(NO

3

)

2

+4H

2

O+2NO

Moles of nitric acid=

63

63

=1

3 moles of copper reacts with 8 moles of nitric acid therefore 1 mole of nitric acid reacts with three-eighth mole of copper.

Therefore, mass of copper=

8

3

×63.5=24 g