Calcule los moles de nitrato de cobre ,Cu(NO3), que se producen si se hacen reaccionar 231.5 gramos de ácido nítrico (HNO3 )
8HNO3 + 3·Cu → 3Cu(NO3)2 + 2NO + 4H2O
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5
Answer:
Value added : Firm A= Rs. 500; Firm B= Rs. 500; Firm C= Rs. 800; Firm D= Rs. 800. (ii) Rs. 2600.
Answered by
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Explanation:
3Cu+8HNO
3
→3Cu(NO
3
)
2
+4H
2
O+2NO
Moles of nitric acid=
63
63
=1
3 moles of copper reacts with 8 moles of nitric acid therefore 1 mole of nitric acid reacts with three-eighth mole of copper.
Therefore, mass of copper=
8
3
×63.5=24 g
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