calculeate (a–2b+c)^3
– (a–2b)^3
–3c (a–2b+c) (a–2b)
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Answer:
(a+2b+3c)2−(a−2b+3c)2−6b2−abc
=a2+4b2+9c2+4ab+12bc+6ac−(a2+4b2+9c2−4ab−12bc+6ac)−6b2−9ac
=a2+4b2+9c2+4ab+12ac+6ac−a2−4b2−ac2+4ab+12bc−6ac−6b2−9bc
=8ab+24bc−6b2−9bc
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Answered by
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Answer:
=c^3
the solution is so long but my answer is correct pls trust me
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