Math, asked by moulimaity324, 5 hours ago

calculeate (a–2b+c)^3
– (a–2b)^3
–3c (a–2b+c) (a–2b)​

Answers

Answered by addyantdixit
0

Answer:

(a+2b+3c)2−(a−2b+3c)2−6b2−abc

=a2+4b2+9c2+4ab+12bc+6ac−(a2+4b2+9c2−4ab−12bc+6ac)−6b2−9ac

=a2+4b2+9c2+4ab+12ac+6ac−a2−4b2−ac2+4ab+12bc−6ac−6b2−9bc

=8ab+24bc−6b2−9bc

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Answered by aWitSu
0

Answer:

=c^3

the solution is so long but my answer is correct pls trust me

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