calculet the mass presenteg of different contituent elements in urea CO (NH2) 2
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And thus
% nitrogen
=
2
×
14.01
⋅
g
⋅
m
o
l
−
1
60.06
⋅
g
⋅
m
o
l
−
1
×
100
%
=
46.6
The molecular mass percentage of 2h2 is 4x1=4and percentage is 4/60*100=6.667
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