Question

calculet the mass presenteg of different contituent elements in urea CO (NH2) 2 ​

Answer 1

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And thus

% nitrogen

=

2

×

14.01

⋅

g

⋅

m

o

l

−

1

60.06

⋅

g

⋅

m

o

l

−

1

×

100

%

=

46.6

The molecular mass percentage of 2h2 is 4x1=4and percentage is 4/60*100=6.667