calculte the normality of the solution 5gm of NaoH in 250.ml of solution
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V=250ml
Normality=gram equivalence/volume
gram equivalence= mass of compound/equivalent weight
equivalent weight is further calculated by dividing the molar mass by its n factor
solving we should get 0.5N
Normality=gram equivalence/volume
gram equivalence= mass of compound/equivalent weight
equivalent weight is further calculated by dividing the molar mass by its n factor
solving we should get 0.5N
misha4:
nice :)
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