Question

Calculus 3 Planes Reivew

Answer 1

Step-by-step explanation:

Given plane is

$P:- 4x - 8y - 2z = - 1$

Since the required plane is parallel to the given plane , so its D.R. will same

so equation of required plane be

$P_{1} :- 4x - 8y - 2z + k = 0$

The point $(8,-7,4)$ lie on $P_{1}$

so,

$- 4(8) - 8( - 7) - 2(4) + k = 0$

$\implies- 32 + 56 - 8 + k = 0$

$\implies- 40 + 56 + k = 0$

$\implies 16 + k = 0$

$\implies k = - 16$

So required equation

$P_{1} :- 4x - 8y - 2z - 16 = 0$

$\implies \: P_{1} :2x + 4y + z + 8 = 0$