Question

Calculus 3 Review Problems

Answer 1

Step-by-step explanation:

Given plane in vector form is

$2x - 5 y + z = 31$

Point$\equiv (-8,-4,-7)$

so,

$d = \frac{ |2( - 8) - 5( - 4) + ( - 7) - 31| }{ \sqrt{ {(2)}^{2} + {( - 5)}^{2} + {(1)}^{2} } }$

$\implies \: d = \frac{ | - 16 + 20 - 7 - 31| }{ \sqrt{ 4+ 2 5 + 1 } }$

$\implies \: d = \frac{ |4 - 38| }{ \sqrt{30 } }$

$\implies \: d = \frac{ | - 34| }{ \sqrt{30 } }$

$\implies \: d = \frac{ 34 }{ \sqrt{30 } }$