Math, asked by justanotherstudent16, 1 year ago

Calculus y=5-(x-1)^2​

Answers

Answered by Anonymous
7

Answer:

\large \text{$-2x+2$}

Step-by-step explanation:

Given :

\large \text{$y=5-(x-1)^2$}

We know derivative of constant term is 0.

And here we will use power formula of differentiation.

\large \text{$x^n=n.x^{n-1}$}

So  d / d x

\large \text{$\dfrac{d}{dx} =5-(x-1)^2$}\\\\\\\large \text{$\dfrac{d}{dx}(5)-\dfrac{d}{dx}[(x-1)^2]$}\\\\\\\large \text{$0-\dfrac{d}{dx}[(x-1)^2$}\\\\\\\large \text{$using \ identity \ (a-b)^2=a^2+b^2-2ab \ here$}\\\\\\\large \text{$-\dfrac{d}{dx}[(x^2+1-2x)]$}\\\\\\\large \text{$-[2x^{2-1}+0-2x^{1-1}]$}\\\\\\\\large \text{$-[2x-2x^0]$}\\\\\\\large \text{$-2x+2$}

Thus we get answer.

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