Physics, asked by mohdu1628, 15 hours ago

Calcutate the focal length of the lead used is simble michoscope that magnifying Power is least distance of distinct vision is 25.0: So The​

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Answered by vivektanwar258
0

Answer:

The magnifying power of a simple microscope is given by M=1+Df, when the final image is at minimum distance of distinct vision. In the question, it is given that the least or minimum distance of distinct vision is 25 cm, and focal length of the microscope is 5 cm. Therefore, the correct answer is option D.

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