Question

Calcutate the total no, of electron present in 1.6g of ch4

Answer 1

Number of moles=given mass/molar mass

Molar mass of methane is 16

N=1.6/16

0.1moles

Second formula

Number of moles=number of electrons/Avogadro's number

0.1=e/6.022*10raised to power 23

e=6.022*10 raised to power 23*0.1

=6.022*10 raised to power 22 is number of electron