Question

Calcute the amount
coq
benzoic acid [CC Hs Cool]
required for prefeating
250ml
of
o.15 h
solution in methyle alchal​

Answer 1

Answer:

Number of moles of benzoic acid required =0.15 ×

250/1000=0.0375 moles

Molar mass of benzoic acid =7(12)+6(1)+2(16)=84+6+32=122 g/mol

Mass of benzoic acid required =122×0.0375=4.575 g

Answer 2

Explanation:

answer:4.575 g......... .........))