Question

calcute the volum of co2 gas produced at stp by the combution of 48 grams of ch

Answer 1

Answer:

Answer: 72 cubic decimeter. Therefore 3moles of CH4 will produce 3 moles of CO2.

Answer 2

Answer: 67.2 lit.( vol of Co2 present in stp by burning of 48 gm ch4)

Explanation: CH4 + 2 O2 ==> CO2 + 2 H2O

16- grams of methane on complete combustion with Oxygen gives

=44- grams of CO2.

So ,48- grams of CH4 on complete combustion gives =

44x48/16=

132 grams of CO2.

So, in stp 1 Mol co2 means 22.4 lit co2

Here, 132 gm. Or( 132÷44) = 3 Mol co2 means

67.2 lit co2