Question

Calcylate th3 relative molecular mass of 0.8g of gas Z occupies 0.56 at sto

Answer 1

Answer:

In your case, you know that your sample of gas occupies  

2.28 L

under STP conditions, which are currently defined as a pressure of  

100 kPa

and a temperature of  

0

∘

C

. This means that your sample will contain  

2.28

L

⋅ molar volume of a gas at STP  

1 mole gas

22.7

L

=

0.10044 moles gas

Now, the molar mass of the gas is the mass of exactly  

1

mole of the gas. In your case, you know that you get  

3.78 g

for every  

0.10044

moles, which means that you have

1

mole

⋅

3.78 g

0.10044

moles

=

37.6 g

Since this is the mass of  

1

mole of gas, you can say that the molar mass of the gas is

molar mass = 37.6 g mol

−

1

−−−−−−−−−−−−−−−−−−−−−−−

Explanation: