Question

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8. If KE of emitted photo electron is 2.5 eV, what is value of stopping potential

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Answer 1

Answer:

Stopping potential =10.4 V

∴Kmax=10.4eV

E=W+Kmax=1.7+10.4=12.1eV

λ=1237512.1=1022Å.

12.1 eV is the energy gap between n = 3 and n=1

in hydrogen atom.

Answer 2

Answer:

ನಢನಡಡನಡನಙಞನಫನಘಧಢಞಬಢಟಠ ಪಡೆದುಕೊಂಡು ಬೆನ್ನಮೇಲೆ ದೊಡ್ಡ ತಪ್ಪು ಲಕ್ಷ್ಮಣರಾವ್