Question

Calealate number of molecules of 20cm³ ofCH4 at o°c and pressure of 700 mmHg of mercury ?​

Answer 1

Answer:

refer to the attachment

Answer 2

Answer:

Given, P1=760mmHg, V1=600mL

  V2=640mL and T2=273+10=283K

According to combined gas law equation,

T1P1V1=T2P2V2

or P2=V2T1P1V1T2

=(640mL)(298K)(760mmHg)×(600mL)×(283K)

= 676.6mmHg