Question

caliculate the mass and volume of oxygen required at STP to convert 2.4kg of graphite into carbon dioxide
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Answer 1

Answer: The equation for the above reaction is as follows:

(graphite is an allotrope of carbon--C)

      C         +       O2 ------->  CO2

        (s)                  (g)                (g)

Therefore 1 mole of graphite requires 1 Mole of O2 to give 1 mole of CO2

Calculate the moles of graphite:

molar mass of C = 12

mass = 2400 g  

moles = mass/molar mass

          = 2400/12

          =200 moles

if 1 mole of C requires 1 mole of O2

then 200 moles requires  = 1 x 200 / 1

                                        = 200 moles

 

           Find mass of oxygen: (molar mass of O2= 32, moles=200)

mass = moles x molar mass

        = 200 x 32

        = 6400g

         = 6.4kg of oxygen

Find the volume of oxygen:

Ideal gas law..... states that 1 mole of an ideal gas occupies 22.4 litres.

                       

                    therefore 200 moles of O2 occupies= (22.4 x 200) liters

   

                                                                              =4480 liters

                volume of oxygen = 4480 liters

PLEASE MARK AS BRAINLIEST.

Answer 2

Explanation:

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