Question

Calls at a telephone switchboard occur at an average rate of 6 calls per 10 minutes. Suppose the operator leaves for a 5-minute coffee break. What is the probability that exactly two calls occur while the operator is away ?

Answer 1

the probability is twothird

Answer 2

Answer:

0.2240

Explanation:

Using the formula of poission distribution :

Here , lambda =6/10, in this case t=5 so that, (lambda t)=3.

Hence the required probability p(2) is given by:

P(2)=e^3 3^2/2! = 3e^3= 0.2240