Calorific value of ethane in kj/g if for the reaction
Answers
Answered by
67
Hey dear,
You didn't mention the reaction.
● Complete question -
Calorific value of ethane, in kJ/g if for the rxn 2C2H6 + 7O2--- 4CO2 + 6H2O ∆H = +746 kcal
● Answer -
Calorific value = -52.22 kJ/g
● Explanation -
In the reaction, 2 ethane molecules are burnt, so heat of combustion is -
∆Hc = -746/2 kcal/mol
∆Hc = -373 kcal/mol
∆Hc = -373×4.2 kJ/mol
∆Hc = -1566 kJ/mol
Calorific value is calculated by -
Calorific value = heat of combustion / molar mass
Calorific value = -1566/30
Calorific value = 52.22 kJ/g
Therefore, calorific value of ethane is 52.22 kJ/g.
* Most imp - keep track on units here.
Hope this helps you...
You didn't mention the reaction.
● Complete question -
Calorific value of ethane, in kJ/g if for the rxn 2C2H6 + 7O2--- 4CO2 + 6H2O ∆H = +746 kcal
● Answer -
Calorific value = -52.22 kJ/g
● Explanation -
In the reaction, 2 ethane molecules are burnt, so heat of combustion is -
∆Hc = -746/2 kcal/mol
∆Hc = -373 kcal/mol
∆Hc = -373×4.2 kJ/mol
∆Hc = -1566 kJ/mol
Calorific value is calculated by -
Calorific value = heat of combustion / molar mass
Calorific value = -1566/30
Calorific value = 52.22 kJ/g
Therefore, calorific value of ethane is 52.22 kJ/g.
* Most imp - keep track on units here.
Hope this helps you...
Answered by
18
from the given data heat of combustion of ethane will be =-745.6 / 2 = -372.8 K cal mol-1
1K cal = 4.18J
∴-372.8 K cal = 372.8 x 4.18 =1559.7959 KJ/mol
Calorific value = heat of combustion/ gram moleculat wt. of fuel = 1559.8 / 30 = 52 KJ /g
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