calucalte no.of valncy electrons present in 4.2g of azide N³-ion
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The total no of valence electrons in 4.2 g of N3- ion I
42 g of N3-contains no of e- = 16. 4.2 g contains = 16 x 4.2 /42. =1.6 valence electrons.
Now ok.
leave it.
it will only make a difference in calculation.
not in the method.
Explanation:
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