Question

Calucalte the difference of delta h and delta u for combustion of 2 moles of benzene 25°c​

Answer 1

Answer:

18 × 298×8.314 = 44.596 kj

Explanation:

delta H = delta U + delta n(g) RT

2 C6H6 + 30 O2 = 12 CO2 + 6 H2O

delta n (g) = 30 -12 = 18