Question

Calucate the number of neutron present of an elements
31
x which is Present as. X?
15

Answer 1

Mass number = No. of protons + No. of neutrons = 31.
∴ Number of neutrons = 31– number of protons.
= 31–15.
= 16.

Answer 2

hey frnd....
given that atomic mass = 31
and no of protons = 15

then we know that
Atomic mass = no of protons + no of Neutron
31 = 15 + no of Neutron
no of Neutron = 16

HOPE THIS HELP YOU ☺☺☺