Question

calucate the required heat energy to change 10 grams of ice at 0 degrees of celcius into watervopur at 100 degree celecius​

Answer 1

Answer:

Explanation

actually for converting 10 gm of ice at 0  degree Celsius to water at 100 degree Celsius will have 2 steps..

first of all ice will convert into water at 0 deg cel.

i.e mL  = 10*80                                            (Latent heat of ice is 80Cal/gm)

            =800 cal..

then water at 0 degree Celsius will convert to water at 100  degree Celsius.

i.e mST = 10*1*(100-0)                              (Specific heat of water is 1Cal/gm/C)

             = 1000 cal

so total energy  = 800+1000

                            =1800 cal       (for converting cal to joule multiply by 4.2)

                            =7560 joule

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