Question

Caluclate the mass 3.011*10^24molecules of nitrogen gas

Answer 1

Ans: 14 grams of N2 have 6.023 *1023number of atoms x grmas of N2 have 3.011*1023 number of atoms x = (14*3.011*1023)/6.023 *1023 = 7 grams  7 grams of N2 contains 3.011*1023 number of atoms.


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