Question

Caluclate the normaility of oxalic acid solution containing 6.3gm of h2c2o4.2h2oin 500ml solution

Answer 1

Answer:

0.2N

Explanation:

Normality=

$\frac{6.3}{63} \times \frac{1000}{500} = 0.2$

where,

Molar weight of H2C2O4.2H2O=126g

Equivalent weight of H2C2O4.2H2O=63g

because n-factor of H2C2O4. 2H2O=2