Question

caluclate the rms speed of nitrogen molecule at 27degrees

Answer 1

Here is your answer buddy ↙️↙️☺️☺️✌️✌️

Given:

m=molar mass of Nitrogen

=28 gm./mol =2.8 x 10 ⁻² kg/mol

Temperature=T=273 +27 =300K

R=gas constant=8.314 joules/.mol K

To calculate RMS speed :

Formula:

μ=√3RT/M

=√(3*8.314*300)/(2.8x10⁻²)

=√267235.7

=516.9m/s

∴RMS of Nitrigen gas at 27 °c is

516.9m/s

Hope this helps you buddy ☺️☺️⭐✨✨⭐✌️✌️❤️❤️❤️