Question

Caluculate the area of the shaded region

Answer 1

Let point in middle be O

in ∆ABO,

By Pythagoras theorem

AB²=12²+5²

AB²= 169

AB =13

Area of ∆ABO

1/2×b×h

1/2×12×5

6×5

=30cm²

In ∆ABC,

1/2×b×h

1/2×AB×BC

1/2×13×15

195/2

=97.5cm²

Area of shader region is =

area of ∆ABC-∆ABO

97.5-30

Area of shaded region is =67.5cm²