Question

caluculate the compound intrest on 18000rs at 10% per annum in two years​

Answer 1

• Compound interest is Rs. 3780 .

Step-by-step explanation:

Given:-

• Principal is Rs. 18000.
• Rate of interest is 10%.
• Time period is 2 years.

To find:-

• Compound interest.

Solution:-

• First we have to find Amount because for Compound interest, Amount is needed.

We know that,

$\boxed{ \star \: \sf \bold{Amount = P(1 + \cfrac{R}{100} )^{n} }}$

In which,

• P is Principal.
• R is Rate of interest.
• n is Time period.

P = Rs. 18000

R = 10%

n = 2 years.

Put , value of P, R and n in formula :

$\longrightarrow \sf \bold{18000( 1 + \cfrac{10}{100}) ^{2} }$

$\longrightarrow \sf \bold{18000 \times ( \cfrac{100 + 10}{100})^{2} }$

$\longrightarrow \sf \bold{180\cancel{00} \times \cfrac{110}{1\cancel{00}} \times \cfrac{110}{100} }$

$\longrightarrow \sf \bold{ \cfrac{21780 \cancel{00}}{1 \cancel{00}} }$

$\longrightarrow \sf \bold{21780}$

Amount = Rs. 21780

$\boxed{\star \: \sf \bold{Compound\: interest = Amount- Principal}}$

$\longrightarrow \sf \bold{21780 - 18000}$

$\longrightarrow \sf \bold{3780}$

Therefore,

Compound interest is Rs. 3780 .