Question

CALUCULATE THE KINETIC ENERGY OF 5 MOLES OF N2 AT 27 DEGREEE CELCIUS

Answer 1

27*5=115byeee hope help

Answer 2

Answered Dec 17 2015 · Author has 346 answers and 529.6k answer viewsFirst of all, let's assume the N2 gas behave as an ideal gas, then the kinefic therory of gases is defined as K.E = 3.R.T/2.n, where R is the universal gas constant, T is the temperature of a gas and n is the number of moles. K.E can be calculated; K.E = [(3 x 8.3145 J/mol.K x (127 + 273)K] / 2 x 4 mol = 1247.175 Joules. The kinetic energy of 4 moles of N2 at 400 K (at 127 C) is 1.25 kJ (1247.175 J).KK7k Views · View UpvotersYour response is private.Is this answer still relevant and up to date?Related QuestionsMore Answers BelowWhat is the formula for the total kinetic energy of a mole of ideal gas molecules?What is the kinetic energy of 2 moles of ideal gas at 127 degrees C?What is average translational kinetic energy in a gas molecules at 27 C?What is the kinetic energy of 3 moles of CO2 gas at 27 degrees?What is the kinetic energy per mole of an ideal gas?Ask New QuestionRhishikesh Jadhav, studied at Wilson College, MumbaiUpdated Mar 24 · Author has 289 answers and 96.3k answer viewsAccording to Kinetic theory of gases, Kinetic Energy of a gas at given temperature isK.E.=32nRTK.E.=32nRTWherenRT=no. of moles of gas=Universal gas constant=Temperature(K)n=no. of moles of gasR=Universal gas constantT=Temperature(K)Therefore, Kinetic Energy of 4 moles of Nitrogen gas at 127°C(400K) will beK.E.=32×4×8.314×400=19953.6JK.E.=32×4×8.314×400=19953.6JNOTE : In this all, I have assumed that nitrogen behaves as an ideal gas1.2k Views · View UpvotersRahul Dev, B.Tech Electronics and Communication Engineering, BNM Institute of TechnologyAnswered Feb 10 · Author has 124 answers and 40.8k answer viewsas we know that nitrogen is a diatomic gas therefore it will have both translational as well as rotational degree of motion.According to Kinetic theory of gases, Kinetic Energy of a gas at given temperature isK.E. = 5/2 *nRTWheren=no. of moles of gasn=no. of moles of gasR=Universal gas constantT=Temperature(K)Therefore, Kinetic Energy of 4 moles of Nitrogen gas at 127°C(400K) will be5/2*4*8.314*400 =33256 joules=8000calall the best.414 ViewsSuryanshu Agrawal, B.tech Civil Engineering, Indian Institute of Technology, Delhi (2021)Answered Jan 4

As nitrogen is a diatomic gas therefore it will have both translational as well as rotational degree of motion. U can calculate kinetic energy by subsituting values in formula 5nRT/2 , where n is no. Of moles, R=8.314 and T is temperature in kelvin.

735 Views · View Upvotersshrikant padhy, studies Studied & Maths and Sciences (2021)Answered Mar 16we know that for a gas enclosed in a cubical vessel, the pressure exhibited by the gas on the wall of vessel will be given by pressure(p)=density*root mean square velocity/3 . which can further be manipulated such that kinetic energy becomes 3*p*v/2 where p stands for pressure and v stand for volume of a gas .according to the ideal gas equation PV=nRT so KE=3*nRT/2WHERE n=no of moles of a gas,R=UNIVERSAL GAS R=8.314J/K*MOL CONSTANT,T=temperature of gas.here after substituting the values the answer comes to be kinetic energy = 19.953KJ .230 ViewsHarry Sharp, BS from United States Naval Academy (1966)Answered Jan 1 · Author has 87 answers and 6.2k answer views

Would there be any kinetic energy if the gas is not moving? E=MV^2. Perhaps I’m thinking of this from a physics angle which is not applicable to chemistry.