Caluculate the mass of benezene requried to produce 22gram of Co2 for the reaction..2C6H6+15 oxygen 2 ---> 12Co2+6H2o
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The molar mass of CO2 is 44g/mol. If you produce 22g, that means you produce 22g/44g/mol = 0.5 mol of CO2.
For 12 moles of CO2, you need 2 moles of benzene. Therefore, for 0.5 mol of CO2, you will need 0.083 mol of benzene (0.5 mol divided by 6 since you need six times less benzene than CO2).
The molar mass of benzene is 78 g/mol. Therefore, 0.083 mol of benzene is 6.47 g (o.083 mol x 78 g/mol).
The answer is 6.47g of benzene is needed.
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