caluculate the ph of 0.001m HCL
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Answered by
4
As we know that, pH = - Log(concentration of hydrogen ion)
= - Log[H+]
[H+] = 0.001 = 1 ×10^(-3)
so, pH = - Log ( 10^(-3))
= - (-3)
= 3
so, pH = 3
= - Log[H+]
[H+] = 0.001 = 1 ×10^(-3)
so, pH = - Log ( 10^(-3))
= - (-3)
= 3
so, pH = 3
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Answered by
1
pH = - Log(concentration of hydrogen ion)
= - Log[H+]
[H+] = 0.001 = 1 ×10^(-3)
so, pH = - Log ( 10^(-3))
= - (-3)
= 3
so, pH = 3
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