caluculate the work done by a person in lifiting a load 20kg from the ground and placing it 1m high on a table.
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Answered by
1
taken g value= 9.8
high = 1m
work done = force × displacement
here force =m×g
work done =mass×accleration due gravity ×displacement
work done= 20× 9.8×1
= 196 joule
high = 1m
work done = force × displacement
here force =m×g
work done =mass×accleration due gravity ×displacement
work done= 20× 9.8×1
= 196 joule
Answered by
0
Force= mg= 20,000×9.8=196000N
work done= force × displacement
= 196000×1
= 196000 J
= 1.96×10^5 J
work done= force × displacement
= 196000×1
= 196000 J
= 1.96×10^5 J
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