Question

Calulate number of CO2 molecules containedin 44.8litre of CO2 at NTP

Answer 1

Volume of carbon dioxide gas = 44.8 L

Since at STP ; 22.4 L = 1 mole of gas

Hence\ 44.8 L=(\frac{1}{22.4}) \times 44.8Hence 44.8L=(

22.4

1

)×44.8

=2 moles of gas.

Hence we can say that at STP; the 44.8 L of carbon dioxide gas contains 2 moles of gas. Here STP indicates the standard temperature and pressure conditions which is 22.4 L volume, at 1 atmospheric pressure and the temperature at 273 K.

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