Question

calulate the amount of NaoH required to prepare 100 ml of 0.1N NaoH solution​

Answer 1

Solution:

Given,

Na = 23 g

O = 16 g

H = 1 g

To make 1N NaOH solution = dissolve 40 grams of NaOH in 1L of water.

To make 0.1N NaOH solution = dissolve 40 grams of NaOH in 1L of water.

To make 0.1N NaOH solution in 100 ml of water:

1000 ml of water = 4 g of NaOH

1 ml of water = (4/1000) g of NaOH

For 100 ml of water = (4/1000) × 100 = 0.4 g of NaOH.

Thus, the amount of NaOH required to prepare 100ml of 0.1N NaOH solution is 0.4 g of NaOH.

Answer 2

Answer:

The answer is 0.4 grams of NaOH

Explanation:

We must use the formula

                 normality =     weight                 x.      1000.      

                                      gram equivalent         volume in ml

                                            weight

           gram equivalent weight of sodium is 40 grams

      using the formula we get

               0.1   =    weight      x  1000

                                40                 100

                 weight = 40x0.1x100  = 0.4 grams

                                    1000