calulate the no. of atom in 3.2 gram of sulphur
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Answer:
Answer. weight of 1mole sulphur=molar mass of sulphur=32g. 1mol has 6.022*10^23 atoms.
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Molar mass of sulphur (S8) = 32 × 8 = 128g
Given Mass of sulphur (S8) = 3.2g
No. of moles = 128/3.2 = 80
No. of atoms = no. of moles × (6.022 × 10^23) =
80 × 6.022 × 10^23 =
8 × 6.022 × 10^24 =
48.176 × 10^24 =
4.818 × 10^25
Hope it helps please mark as brainliest
Given Mass of sulphur (S8) = 3.2g
No. of moles = 128/3.2 = 80
No. of atoms = no. of moles × (6.022 × 10^23) =
80 × 6.022 × 10^23 =
8 × 6.022 × 10^24 =
48.176 × 10^24 =
4.818 × 10^25
Hope it helps please mark as brainliest
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