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the line represented by equation x²-
2xy-3y²=0
are distinct.
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Answered by
17
Answer:
The Line x²- 2xy - 3y² = 0 is quadratic in nature thus, we can find the two equations by solving the equation.
⇒x²- 2xy - 3y² = 0
⇒x² + xy - 3xy - 3y² = 0
⇒x(x + y) -3y(x + y) = 0
⇒(x - 3y)(x + y) = 0
∴ the two equations are x - 3y; x + y
for the two equations to have distinct roots a₁/a₂ ≠ b₁/b₂
⇒1/1 ≠ -3/1
∴ The Lines Represented by the equation are distinct.
Answered by
0
Answer:
The Given Equation x2-2xy-3y2=0 x2-xy-3xy-3y2=0
x-(x-y) -3(x-y)=0
we get two equation
(x-3) (x-y)
The distinct root
a1/a2 =not b1/b2
1/1=not -3/1
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