campare in power
a butterfiy mass 1gm and having velocity -0.5ms
250gm of toy having velocity-0.5ms
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Answered by
2
weight of butterfly = 0.001 ×10 g=(9.8)
= 0.01 N
v= 0.5 m/s
power = Force × velocity
= 0.01× 0.5
= 0.05
weight of butterfly = 0.250 × 10
= 2.50
v= 0.5
Power = 2.50 × 0.5
= 6.250
Hence power exerted by the toy is more than that of butterfly.
Weight of toy = 250 ×10
= 2500
= 0.01 N
v= 0.5 m/s
power = Force × velocity
= 0.01× 0.5
= 0.05
weight of butterfly = 0.250 × 10
= 2.50
v= 0.5
Power = 2.50 × 0.5
= 6.250
Hence power exerted by the toy is more than that of butterfly.
Weight of toy = 250 ×10
= 2500
Anonymous:
mai confused
Answered by
2
As we know Power=Force ×Velocity
As Force=m×g ;g=10 m/s²
P(butterfly)=1 ×10^-3× 10 ×0.5
P(Toy)=250 ×10^-3× 10 ×0.5
----------
P(butterfly)/P(Toy)
==> 1/250
The ratio of their power is 1:250
As Force=m×g ;g=10 m/s²
P(butterfly)=1 ×10^-3× 10 ×0.5
P(Toy)=250 ×10^-3× 10 ×0.5
----------
P(butterfly)/P(Toy)
==> 1/250
The ratio of their power is 1:250
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