campare the time of two simple pendulm of length of 1 m and 16 m at a place
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Answer:
time period of pendulum 16m is 4 times the time period of 1m pendulum.
Explanation:
We know time period of pendulum is equal to 2π√l/g
Suppose T1 and T2 be the time period of pendulum having length 1m and 16 m
Now T1 will be T1=2π√1/g
and T2 will be T2=2π√16/g
Divinding T1 and T2
T1÷T2 = 1÷4 (2π and g will cancel out while divinding you can check by solving)
T2=4T1
this results means that time period of pendulum 16m is 4 times the time period of 1m pendulum.
Have a good day ☺️
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