Question

Campingequipmentweighing6000Nispulled

across a frozen lake by means of a horizontal

rope. Thecoefficient of kinetic friction is 0.05.

The work done by the campers in pulling the

equipment 1000 m at constant velocityis

Answer 1

Here constant velocity means force should be equal to the friction force
So f = mg*0.05=6000*0.05=300N
Hence w = f *d = 300*1000=3*10^5j