Math, asked by zainabalearners, 1 year ago

Can 1947 be the sum of 11 consecutive terms of any arithmetic sequence?

Answers

Answered by rahulkumar4120
0
Let consceutive number be x;x+1 x+2;x+3nx+4; x+5; x+6; x+7; x+8; x+9; x+10
A/q;
11x+55=1947
11x=1947-55
11x=1892
X=1892/11
X=172
So 1x+172
All value are put like that
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