Math, asked by sheetalchug99, 9 months ago

can 2 no have 18 as their hcf and 290as their lcm

Answers

Answered by amitsnh

0

Answer:

No

Step-by-step explanation:

LCM is always divisible by HCF

in this case 290 is not divisible by 18 so they cannot exist together as LCM and HCF

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