can 2x^2+3 be the n th term of an AP. justify ?
Answers
Answered by
1
Answer: No...
Step-by-step explanation:
f(x)= 2x^2+3
f(1)= 2*1+3 = 5
f(2)= 2*4+3 = 11
f(3)= 2*9+3 = 21......
So, we can see that the difference of the progression is not constant but is increasing..
Hence, it can not be an AP..
I hope u got ur answer...
Similar questions