Question

can 4^n ends with zero?( where 'n' is a natural number) prove your answer.​

Answer 1

Answer:

No.

Explanation :

We have $4^n$ , where n is a natural number.

so, n= 1,2,3,4...

$\sf \: if \: n = 1 \: \: then \: {4}^{1} = 4 \\ \sf \: if \: n = 2 \: \: then \: {4}^{2} = 16 \: \: \: and \: so \: on \:$

Again, if a number ends with zero then it is divisible by 5

Here, 4, 16 are not dividible by 5.

Therefore, $4^n$ can never end with zero.

Hence proved.