can a body have a chage of 0.32×10-18C
Answers
Answered by
3
we know that, q =ne
where n is an integer.
so, 0.32 * 10^(-18) = n* (1.6*10^(-19))
0.32 * 10^(-18) / (1.6*10^(-19)) = n
2= n = integer,
therefore, yes a body can have a charge of 0.32×10-18C ;)
where n is an integer.
so, 0.32 * 10^(-18) = n* (1.6*10^(-19))
0.32 * 10^(-18) / (1.6*10^(-19)) = n
2= n = integer,
therefore, yes a body can have a charge of 0.32×10-18C ;)
Anonymous:
hello
hi
Similar questions