Can a concave mirror produce a magnification +1? It yes/no, explain. HOW?
Answers
Answer: plese give feedback
Explanation:
Mirror formula : 1/v +1/u = 1/f
Magnification of a mirror, m = -v/u
Where u= object distance, v = image distance and f = focal length
Let's consider an example:
A concave mirror has focal length 10 cm and object is placed at distance 15 cm from pole of mirror. Calculate image distance and magnification produced.
Solution: Using mirror formula,
1/v +1/u = 1/f
1/v + 1/-15 = 1/-10
1/v = 1/15 -1/10 = (2 - 3)/30 = -1/30
So, v = -30 cm
Now magnification, m = -v/u = 30/-15 = -2
Thus image is real, inverted and double in size.
no
Explanation:
the mirror formula is 1/v+1/u=1/f
where
u is the distance of the object from the mirror
v is the distance of the image from mirror
and f is the focal lenght
the distance from the mirror to the left is taken as negative and the distance to right is taken as positive
the magnification =hi/ho =-v/u where
hi is the hight of the image
ho is the hight of the object
the distance above the principal axis ia taken as positive and the distance below the principal axis ia taken as negative
1/v+1/u =1/f. so
1/v=1/f-1/u =u-f/uf
if the magnification is 1 then...
v=-u so...
uf/u-f= -u
uf=-uf^2 + uf so..
u =0 which is not possible ...
....... i hope it helps...
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