can a polyhedron have 10 faces , 20 edges, and 15 vertices ?
Answers
Answered by
639
no a polyhedron cant have 10 faces , 20 edges, and 15 vertices as eulers formula is not satisfied
euler's formula = faces+ vertices-edges = 2
10 + 15-20 = 2
25-20 = 2
5 2
so it cant have 10 faces , 20 edges, and 15 vertices
euler's formula = faces+ vertices-edges = 2
10 + 15-20 = 2
25-20 = 2
5 2
so it cant have 10 faces , 20 edges, and 15 vertices
Answered by
299
No.It can't have 10 faces , 20 edges, and 15 vertices as The formula i.e. Euler's formula isn't being satisfied.
According to the formula....
(F+V)-E=2
Where,
F=>faces=10
E=>edges=20
V=>vertices=15
(F+V)-E=2
(10+15)-20=2
25-20=2
but
5≠2
so,the Euler's formula is not satisfied.
Therefore,A polyhedron cannot have 10 faces , 20 edges, and 15 vertices.
According to the formula....
(F+V)-E=2
Where,
F=>faces=10
E=>edges=20
V=>vertices=15
(F+V)-E=2
(10+15)-20=2
25-20=2
but
5≠2
so,the Euler's formula is not satisfied.
Therefore,A polyhedron cannot have 10 faces , 20 edges, and 15 vertices.
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