Can a polyhedron have 8 faces, 14 edges and 6 vertices? Specify reason.
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Step-by-step explanation:
Number of faces =8
Number of vertices =16
Number of edges =26
Using Euler’s formula :-
F+V−E=2
8+16−26
8+16−26
−2 is not equal to 2
No, a polyhedron cannot have 8 faces, 26 edges and 16 vertices
Answered by
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Step-by-step explanation:
No, a polyhedron cannot have 8 faces, 26 edges and 16 vertices.
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