Question

Can a right triangle with sides 6cm,10cm and 8cm be formed? Give reasons​

Answer 1

Answer:

yes

Step-by-step explanation:

since sum of squares of two sides is equal to square of third side, it is right abgled triangle

$\sqrt{ {8}^{2} + {6}^{2} } = \sqrt{64 + 36} = \sqrt{100} = \sqrt{ {10}^{2} } = 10$

Answer 2

Answer:

yes

Step-by-step explanation:

By using pythagoras theorem

AC^2 = AB^2 + BC^2

10^2 = 6^2 + 8^2

100 = 36 + 64

100 = 100

root 100 = root 100

10 = 10

LHS = RHS

Hence proved .