Chemistry, asked by Nareshk8782, 8 months ago

Can a solution of 1m copper sulphate be stored in a vessel made of nickel metal

Answers

Answered by Anonymous
3

Ni + CuSO4 à NiSO4+ Cu

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + Cu

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented as

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I Cu

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I CuOxidation potential are given as

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I CuOxidation potential are given asE0Ni+2,Ni = -E0Ni,Ni+2 =0.25 volt

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I CuOxidation potential are given asE0Ni+2,Ni = -E0Ni,Ni+2 =0.25 voltAnd E0Cu+2,Cu = -E0Cu,Cu+2 = +0.34 volt

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I CuOxidation potential are given asE0Ni+2,Ni = -E0Ni,Ni+2 =0.25 voltAnd E0Cu+2,Cu = -E0Cu,Cu+2 = +0.34 voltHence E0cell = E0RHS electrode – E0LHS electrode

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I CuOxidation potential are given asE0Ni+2,Ni = -E0Ni,Ni+2 =0.25 voltAnd E0Cu+2,Cu = -E0Cu,Cu+2 = +0.34 voltHence E0cell = E0RHS electrode – E0LHS electrode = +0.34 – (- 0.25)=0.59volt

Ni + CuSO4 à NiSO4+ CuNi + Cu+2 à Ni+2 + CuBy convention, the cell may be represented asNi I Ni+2 II Cu+2I CuOxidation potential are given asE0Ni+2,Ni = -E0Ni,Ni+2 =0.25 voltAnd E0Cu+2,Cu = -E0Cu,Cu+2 = +0.34 voltHence E0cell = E0RHS electrode – E0LHS electrode = +0.34 – (- 0.25)=0.59voltThe EMF is positive and which implies that CuSO4 reacts with nickel. Hence CuSO4 cannot be stored in nickel vessel.

Answered by chaudharyabhinav334
1

Answer:

yes a solution of 1m copper sulphate be srored

Similar questions