Question

can a sum of an number and its reciprocal be 2/3.why?​

Answer 1

Answer:

NO

Step-by-step explanation:

Let the number be 'x',

x+ $\frac{1}{x}$= $\frac{x^2 + 1}{x}$=$\frac{2}{3}$

3x^2+3=2x

3x^2-2x+3=0

D<0, thus roots are imaginary

:. no real number exists for which sum of the number and its reciprocal is 2/3.